Question

Ajutați-mă vă rog cineva cu problema IV.

Answer 1

Răspuns:

yt=3sin(100πt+π/3)

a. pulsatia ω=100π

amplitudinea=3

faza initiala=π/3

b. yo=3sin(100·0+π/3)=3sin(0+π/3)=

3sinπ/3=3√3/2

c. ecuatia vitezei

v=3*100πcos (100πt+π/3)=

300πcos(100πt+π/3)

vmax . pui conditia ca 100πt+π/3=2π

100πt=2π-π/3

100πt=5π/3

100t=5/3

t=5/3*100=1/60s

vmax=300π

d.a=-3·(100π)²sin(100πt+π/3)=

-30000π²sin(100πt+π/3)

amax=-30000π²

Iti scriu imediat si perioada si frecventa

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perioada T

ω=2π/T

T=2π/ω=2π/100π=1/50s

T=1/50s

frecventa f=1/T=50

Gata

Explicație: