Question

Ajutati.ma va rog!!dau corinita

Answer 1

Triunghiul ABC este dreptunghic, m(A)=90 grade, AD⊥BC rezulta din teorema inaltimii $AD^2=DB*DC$

a)BD=BC-DC
DB=70-63=7

$AD^2=DB*DC$=7*63
AD=$\sqrt{7*63}=21$

b)DC=BC-BD=26-8=18
AD=$\sqrt{DB*DC}= \sqrt{18*26}=6 \sqrt{13}$

c)$AD^2=DB*DC$, deci
$12^2=BD*16$
BD=144/16=9
BC=BD+DC=9+16=25

d)$AD^2=DB*DC$, deci
$12^2=DC*27$
BD=144/27=6/3
BC=BD+DC=27+6/3=87/3

e)BC=BD+DC=0.25+5=5.25
$AD^2=DB*DC=0.25*5=1.25$
$AD=\sqrt{1.25}=0.5\sqrt{5}$

f)DC=BC=BD=6.5-1.5=5
$AD^2=DB*DC=1.5*5=7.5$
$AD=\sqrt{7.5}=0.5\sqrt{30}$