Question

ajutați mă va rog dau coroana ​

Answer 1

$a)~\Big[(-2)^3+3 \cdot(-1)^3+(-6):(-3)\Big]\cdot 10=[(-8) +3 \cdot (-1)+2]\cdot 10=\\\\=[(-8)-3+2]\cdot 10=[(-11)+2] \cdot 10=(-9) \cdot 10=-90$

$\displaystyle b)~A=\sqrt{81} \cdot \sqrt{2} \cdot \sqrt{8} =9 \cdot \sqrt{2} \cdot 2\sqrt{2} =9 \cdot 2 \cdot 2=18 \cdot 2=36\\\\B=(-1) \cdot \Big[(-3)^{15}:3^{14}+(-1) \cdot (-2)\cdot (-3)+(10-17)\Big]=\\\\=(-1) \cdot \Big[(-3)^{15-14}+2 \cdot(-3)+(-7)\Big]=(-1) \cdot [(-3)-6-7]=\\\\=(-1) \cdot [(-9)-7]=(-1) \cdot (-16)=16\\\\ m_a=\frac{A+B}{2} =\frac{36+16}{2} =\frac{52}{2} =26\\\\ m_g=\sqrt{a \cdot b} =\sqrt{36 \cdot 16} =\sqrt{576}= 24$

$\displaystyle c)~\sqrt{81} =9,~(-5)^2=25\\\\ m_a=\frac{9+25}{2} =\frac{34}{2} =17\\\\ m_g=\sqrt{9 \cdot 25}=\sqrt{225} = 15$