Question

ajutati-ma va rog fau cororana va rog
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Answer 1

Răspuns:

buna, sper că te am ajutat!!

Answer 2

$\displaystyle A=\{x\in\mathbb{R}~/~5-3(2x+1) > -4\}\\\\ 5-3(2x+1) > -4 \Rightarrow 5-6x-3 > -4 \Rightarrow -6x > -4+3-5 \Rightarrow \\\\ \Rightarrow -6x > -6 \Rightarrow 6x < 6 \Rightarrow x < \frac{6}{6} \Rightarrow x < 1\Rightarrow x\in (-\infty,1)~~~~~\boxed{d}$