Question

Ajutati.ma va rog la aceste 2 exercitii!Dau coroana

Answer 1

3.

2^x+2^(x+3)=36

2^x+2x•2^3=36

2^x(1+8)=36

2^x=36/9

2^x=4

2^x=2^2=>(injectivitatea functiei exponentiale):x=2

4.

4!/(4-4)!+4!/[(4-4)!4!]=4!/0!+1/0!=(24+1)/0!=25/0!=25

Prin conventie 0!=1