Question

Ajutati-ma va rog la ex 25 ! Dau coroana!

Answer 1

a) x+1|x+13
x+1|x+1
le scazi si obtii:
x+1|12
x+1 apartine {1;2;3;4;6;12}
x apartine {0;1;2;3;5;11}

b) x+2|5x+12
x+2|x+2 /×5
x+2|5x+10
dar x+2|5x+12
le scazi si obtii:
x+2|2
x+2 apartine {1;2}
x=0

c) (4x+33) divizibil cu (x+3)
=> x+3|4x+33
x+3|x+3 /×4
x+3|4x+12
dar x+3|4x+33
le scazi si obtii:
x+3|21
x+3 apartine {1;3;7;21}
x apartine {0;4;18}

Sper ca te-am ajutat!