Question

Ajutaţi-mă va rog la exercițiul 3 .

Answer 1

cazuri favorabile:2;4;6-->3 numere
cazuri posibile:1;2;3;4;5;6-->6 numere
p%=3/6*100=300/6=50

3 caiete........8,4 lei x=8,4*5/3=42/3=14
5 caiete........x lei

3/9=x/15=4/12
1/3=x/15=1/3
1/3=x/15 x=15/3=>x=5

7*15=3*35=21*x
105=105=21x
21x=105=>x=5