Question

ajutati-ma va rog la exercitiul 39

Answer 1

Aici este rezolvarea exercițiului

Answer 2

39) [tex]a)a(x+y)+bx+by=a(x+y)+b(x+y)=(x+y)(a+b) \\ b)21x^2-7xy+11(3x-y)=7x(3x-y)+11(3x-y)=\\ =(3x-y)(7x+11)[/tex]
[tex]c)3x+6y+mx+2my=3(x+2y)+m(x+2y)=(x+2y)(3+m) \\ d)12mx-4my^2+15ax-5ay^2=4m(3x-y^2)+5a(3x-y^2)= \\ =(3x-y^2)(4m+5a) \\ [/tex]
[tex]e)a^2+b^2+6a^2x+6b^2x=a^2(1+6x)+b^2(1+6x)=(1+6x)(a^2+b^2)\\ f)2m+n^2+2mx^2+n^2x^2=2m(1+x^2)+n^2(1+x^2)=\\=(1+x^2)(2m+n^2)[/tex]
Mult succes in continuare!