Question

Ajutati-ma, va rog! Multumesc frumos!

Answer 1

[tex]\displaystyle Se~da:\\ \\ V=500l=0,5m^3\\ \\ \rho=800\frac{kg}{m^3}\\ \\ pe=10\%\Rightarrow \eta=90\%=0,9\\ \\ m_u=?kg\\ \\ \\ Formule:\\ \\ \eta=\frac{m_u}{m_t}\\ \\ \eta=\frac{m_u}{V\times \rho}\\ \\ m_u=\eta\times V\times\rho\\ \\ \\ Calcule:\\ \\ m_u=0,9\times 0,5\times 800=360kg [/tex]