Question

 Ajutati-ma va rog sa rezolv ecuatia : 2x+4 x+6x+...+300 x-50=x+3x+5 x+299 x+100

Answer 1

2x+4x+6x+......+300x-50=x+3x+5x+299x+100
2x(1+2+3+......+150)-50=308x+100
2x(150*151:2)-50=308x+100
2x(22650:2)-50=308x+100
2x*11325-50=308x+100
22650x-50=308x+100
22650x-308x=100+50
22342x=150
x=150:22342

Aceasta este rezolvarea problemei. Exista posibilitatea ca ceva sa nu fie completat ok din manual.

Answer 2

folosesti formulele 
2+4+...+n=1/2n(1/2n+1)
si 
1+3+5+...+n=[(n+1):2]²

x(2+4+...+300)-50=x(1+3+5+..299)+100
x(150*151)-50=x(300:2)²+100
x*22650-50=x*22500+100
22650x-22500x=100+50
150x=150
x=150:150
x=1