Question

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$1 \frac{2}{25} \div 1 \frac{5}{49} + 1 \frac{1}{35} \div 2 \frac{6}{7} =$
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Answer 1

Răspuns:

$1 \frac { 2 } { 25 } : 1 \frac { 5 } { 49 } + 1 \frac { 1 } { 35 } : 2 \frac { 6 } { 7 }$

$\frac{\left(1\times 25+2\right)\times 49}{25\left(1\times 49+5\right)}+\frac{\frac{1\times 35+1}{35}}{\frac{2\times 7+6}{7}}$

$\frac{\left(25+2\right)\times 49}{25\left(1\times 49+5\right)}+\frac{\frac{1\times 35+1}{35}}{\frac{2\times 7+6}{7}}$

$\frac{27\times 49}{25\left(1\times 49+5\right)}+\frac{\frac{1\times 35+1}{35}}{\frac{2\times 7+6}{7}}$

$\frac{1323}{25\left(1\times 49+5\right)}+\frac{\frac{1\times 35+1}{35}}{\frac{2\times 7+6}{7}}$

$\frac{1323}{25\left(49+5\right)}+\frac{\frac{1\times 35+1}{35}}{\frac{2\times 7+6}{7}}$

$\frac{1323}{25\times 54}+\frac{\frac{1\times 35+1}{35}}{\frac{2\times 7+6}{7}}$

$\frac{1323}{1350}+\frac{\frac{1\times 35+1}{35}}{\frac{2\times 7+6}{7}}$

$\frac{49}{50}+\frac{\frac{1\times 35+1}{35}}{\frac{2\times 7+6}{7}}$

$\frac{49}{50}+\frac{\left(1\times 35+1\right)\times 7}{35\left(2\times 7+6\right)}$

$\frac{49}{50}+\frac{1+35}{5\left(6+2\times 7\right)}$

$\frac{49}{50}+\frac{36}{5\left(6+2\times 7\right)}$

$\frac{49}{50}+\frac{36}{5\left(6+14\right)}$

$\frac{49}{50}+\frac{36}{5\times 20}$

$\frac{49}{50}+\frac{36}{100}$

$\frac{49}{50}+\frac{9}{25}$

$\frac{49}{50}+\frac{18}{50}$

$\frac{49+18}{50}$

$\frac{67}{50}$

$\frac{67}{2 \cdot 5 ^ {2}} = 1\frac{17}{50} = 1.34$

Answer 2

Explicație pas cu pas:

$1 \frac{2}{25} \div 1 \frac{5}{49} + 1 \frac{1}{35} \div 2 \frac{6}{7} = \\ = \frac{27}{25} \div \frac{54}{49} + \frac{36}{35} \div \frac{20}{7} \\ = \frac{ \not27}{25} \times \frac{49}{ \not54} + \frac{ \not36}{ \not35} \times \frac{ \not7}{ \not20} \\ = \frac{1}{25} \times \frac{49}{2} + \frac{18}{5} \times \frac{1}{10} \\ = \frac{49}{50} + \frac{18}{50} = \frac{49 + 18}{50} \\ = \frac{67}{50} = 1 \frac{17}{50} = 1.34$