Question

Ajutati-ma va rogg !!!

Answer 1

A) Ducem BE_|_DC. Avem si BE=AD

Deoarece triunghiul BCD este dreptunghic, avem BE²=DE×EC (teorema inaltimii).

Dar DE=AB=18cm si EC=DC-DE=50-18=32cm

Deci BE²=18×32=9×2×8×4=9×8²=3²×8²=24².

Deci BE=AD=24cm

B) BC²=EC×DC=32×50=32×2×25=64×25= 8²×5²=40²

Deci BC=40cm

P_ABCD=AB+BC+CD+AD=18+40+50+24= 42+90=132cm

P_ABCD=132cm