Question

Ajutați-mă vă roggg dau punctaj maximm!!!!
1. (6×^3y^2+5x^2y)^2
2. (1,2x^2y+0,5x^3y^2)^2
3. (3x-2y)^2
4. (5a^b-2ab)^2

Answer 1

a)

(6x³y²+5x²y)²=

(x²y(6xy+5))²=

(x²)²y²(6xy+5)²=

x⁴y²(6xy+5)²

b)

(1,2x²y+0,5x³y²)²=

(x²y(1,2+0,5xy))²=

(x²)²y²(1,2+0,5xy)²

x⁴y²(1,2+0,5xy)²

c)

(3x-2y)²=

(3x)²-2•3x•2y+(2y)²=

3²x²-2•3x•2y+(2y)²=

9x²-2•3x•2y+2²y²=

9x²-12xy+4y²

$d) \\ \\ ( {5a}^{b} - 2ab) ^{2} = \\ \\ ( {5a}^{b}) ^{2} - 2 \times {5a}^{b} \times 2ab + {(2ab)}^{2} = \\ \\ {5}^{2}( {a}^{b}) ^{2} - 2 \times {5a}^{b} \times 2ab + {(2ab)}^{2} = \\ \\ 25( {a}^{b}) ^{2} - 2 \times {5a}^{b} \times 2ab + {(2ab)}^{2} = \\ \\ {25a}^{b \times 2} - 2 \times {5a}^{b} \times 2ab + {(2ab)}^{2} = \\ \\ {25a}^{2b} - 2 \times {5a}^{b} \times 2ab + {(2ab)}^{2} = \\ \\ {25a}^{2b} - 2 \times {5a}^{b} \times 2ab + {2}^{2} {a}^{2} {b}^{2} = \\ \\ {25a}^{2b} - 2 \times {5a}^{b} \times 2ab + {4a}^{2} {b}^{2} = \\ \\ {25a}^{2b} - (2 \times 5 \times 2) {a}^{b}ab + {4a}^{2} {b}^{2} = \\ \\ {25a}^{2b} - 20 {a}^{b}ab + {4a}^{2} {b}^{2} = \\ \\ {25a}^{2b} - {20a}^{b + 1}b + {4a}^{2} {b}^{2}$