Question

Ajutați-ma va roog!!!

Answer 1

[tex] \frac{ \sqrt[3]{10+ \sqrt{32} } \sqrt[3]{10- \sqrt{32}} }{ \sqrt[6]{16} }= \frac{ \sqrt[3]{(10+ \sqrt{32})(10- \sqrt{32})}}{ \sqrt[6]{ 2^{4}}}= \frac{ \sqrt[3]{100-32} }{ \sqrt[3]{ 2^{2}}}= \frac{ \sqrt[3]{4*17}}{ \sqrt[3]{4} }[/tex]= $\sqrt[3]{17}$