Question

ajutati maaaa ex 8.......​

Answer 1

BM=18

MC=32

BC=18+32=50

Aplicam teorema inaltimii in BOC dr in O

OM²=BM×MC

OM=√18×32

OM=√576=24cm

$A_{BOC}=\frac{OM\times BC}{2}=\frac{24\times 50}{2}=600cm^2$

$A_{ABCD}=4\times A_{BOC}=2400cm^2$