Question

Ajutati va rog urgent )) sa rezolv

Answer 1

a)   -x=3     x=-3
la b nu se vede puterea lui 8
c) 7-3x=-(x-4)    7-3x=-x+4     2x=3  x=3/2
d) 2x-3=0   x=3/2
e) 2(2x-3)=-1    4x-6=-1 x=5/4
f) 2x+3=x-2  x=-5
g) 2x=-3   x=-3/2
h) x²-1=3   x=2
i)   4x=1   x=1/4
k)  -1,5x+3=2  x=2/3
l) 5x+6=2    x=-4/5

Answer 2

$9^{-x} = 27 [tex] 9^{-x}$=$3^{3}$
-x=3
x=-3


$8^{x} =16[tex] [tex] 2^{3x} =[tex] 2^{4} [tex] 3x=4 x=[tex] \frac{4}{3}$

$2^{7-3x} = (\frac{1}{2} ) ^{x-4}$



 2^{7-3x} = $2^{-x+4}$
7-3x=-x+4
7-4=-x+3x
3=2x
x=$\frac{3}{2}$


$0,8^{2x-3} =1$
$0,8^{2x-3} =[tex] 0,8^{0}$
2x-3=0
2x=3
x=$\frac{3}{2}$


$4^{2x-3} =0,5$

[tex] 4^{2x-3} = \frac{5}{10}[tex]

 [tex] 4^{2x-3} = \frac{1}{2} [/tex]

$2^{2(2x-3)}$=$2^{-1}$
2(2x-3)=-1
4x-6=-1
4x=6-1
4x=5
x=$\frac{5}{4}$


$(\frac{2}{9} )^{2x+3} = 4,5^{x-2}$
$\frac{2}{9} ^{2x+3} = \frac{9}{2} ^{x-2}$
$\frac{2}{9} ^{2x+3} = \frac{2}{9} ^{-x+2}$
2x+3=-x+2
2x+x=2-3
x=-1

$36^{x} = \frac{1}{216}$
$6^{2x}$=$6^{-3}$
2x=-3
x=-$\frac{3}{2}$


[tex] 5^{ x^{2} -1} =125 [/tex]

$5^{ x^{2} -1} =[tex] 5^{3}$
$x^{2} -1$=3
$x^{2}$=4
x=2  x=-2



$10^{2x} =0,1 \sqrt{1000}$
$10^{2x} =0.1*10√10 [tex] 10^{2x} =√10 [tex] 10^{2x} =[tex] 10^{1/2}$
2x=$\frac{1}{2}$
x=$\frac{1}{4}$



$2- 3^{ x^{2} -1} =1$

$3^{ x^{2} -1} =1^{0}$

$x^{2}$-1=0
$x^{2}$=1
x=1  x=-1


$(\frac{1}{8} ) ^{0,5x-12} =2$

-3(0,5x-12)=1
-0,15x+36=1
-0,15x=-35
x=233,(3)


$7^{5x+6}$=49
5x+6=2
5x=-4
x=-$\frac{4}{5}$