Question

Ajutatima sa rezolv urmatorul sistem de ecuatii de 2 necunoscute prin metoda reducerii:
{x-4y=2
{3x-2y=16

Answer 1

$\left \{ {{x-4y=2} \atop {3x-2y=16}} \right.$ ⇔$\left \{ {{-3x+12y= -6} \atop {3x-2y=16}} \right.$⇔$\left \{ {{-3x+12y= -6} \atop {-10y= -10}} \right.$⇔$\left \{ {{-3x+12y= -6} \atop {y=1}} \right.$⇔$\left \{ {{-3x+12*1=-6} \atop {y=1}} \right.$⇔$\left \{ {{-3x=18} \atop {y=1}} \right.$⇔$\left \{ {{x=6} \atop {y=1}} \right.$