Question

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Answer 1

a+c=(-3)

b=12

a×b+b×c

a×12+12×c=

=12a+12c(dăm factor comun)

=12(a+c)

=12×(-3)

=-36

Answer 2

Răspuns:

Explicație pas cu pas:

15.a=-72=-2³×3²

b=156=2²x3x13

c=-200=-2³×5²

16.a+c=-3

b=12

a×b+b×c =?

inlocuim b in relatia:

a×b+b×c

a×12+c×12=

=12(a+c)

=12×(-3)

=-36

17. a=8

a×b- a×c=-120

b-c=?

inlocuim a in relatia:

a×b- a×c=-120

8×b-8×c=-120

8(b-c)=-120

b-c=-120:8

b-c=15

18. a=0

b=1

c=2

d=3

a+b+c+d=0+1+2+3

a×b×c×d=0×1×2×3=0

19.

a)a=-7

b=-2

c=0

a×b+b×c=-7×(-2)+(-2)×0=14+0=14

a-2×b+3×c=-7-2×(-2)+3×0=-7+4+0=-3

b×(c-b)=-2×[0-(-2)]=-2x2=-49

-2×(a-b+c)+3×(2a-b+3c)=-2×[-7-(-2)+0]+3×[2×(-7)-(-2)+3×0]=-2×(-7+2)+3×(-14+2)=-2×(-5)+3×(-12)=10-36=-26

b)a=-5

b=3

c=-1

a×b+b×c=(-5)x3+3x(-1)=-15-3=-18

a-2×b+3×c=-5-2x3+3x(-1)=-5-6-3=-14

b×(c-b)=3x(-1-3)=3x(-4)=-12

-2×(a-b+c)+3×(2a-b+3c)=-2x(-5-3+(-1))=-2x(-9)=18

c)a=-3

b=-2

c=-4

a×b+b×c=(-3)x(-2)+(-2)x(-4)=.....

a-2×b+3×c=......

b×(c-b)=........

-2×(a-b+c)+3×(2a-b+3c)=........

d)a=5

b=-1

c=-3

a×b+b×c=..........

a-2×b+3×c=........

b×(c-b)=.........

-2×(a-b+c)+3×(2a-b+3c)=...........