Question

Ajutatima va rog cum pot simplifica sa aflu a
$a = 25^\frac{1}{log_8 5}$

Answer 1

[tex]log_ab = \frac{1}{log_ba} atunci \frac{1}{log_8 5} = \frac{1}{\frac{1}{log_58}} = log_58[/tex] 
$=\ \textgreater \ a = (5^{2})^{log_58} =\ \textgreater \ a = 5^{2log_58} =\ \textgreater \ a = 5^{log_516} =\ \textgreater \ a = 16$
conform formulei $a^{log_ax} = x$ ∀ x > 0