Question

Ajutatima va rog dau coronita
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Answer 1

$a = 1 \frac{3}{2} + 2 \frac{2}{3} - 4 \frac{3}{4} \\ \\ a = \frac{5}{2} + \frac{8}{3} - \frac{19}{4} \\ \\ a = \frac{30 + 32 - 57}{12} \\ \\ a = \frac{5}{12} \\ \\ \\ \\ b = 2 \frac{5}{50} \cdot \frac{8}{7} : \frac{24}{10} \\ \\ b = \frac{105}{50} \cdot \frac{8}{7} : \frac{24}{10} \\ \\ b = \frac{15}{25} \cdot 4 \cdot \frac{10}{24} \\ \\ b = \frac{12}{5} \cdot \frac{10}{24} \\ \\ b =12 \cdot \frac{2}{24} \\ \\ b = 1 \\ \\ \iff \: \frac{5}{12} \boxed{< } \frac{12}{12}$

Answer 2

$\it a=3\dfrac{1}{2}+2\dfrac{2}{3}-4 \dfrac{3}{4}=(3+2-4)+( \dfrac{^{6)}1}{\ 2}+ \dfrac{^{4)}2}{\ 3}- \dfrac{^{3)}3}{\ 4})=1+ \dfrac{6+8-9}{12}=1 \dfrac{5}{12}\\ \\ \\ b=2 \dfrac{5}{50}\cdot \dfrac{8}{7}\cdot \dfrac{24}{10}= \dfrac{\ \ 105^{(5}}{50}\cdot \dfrac{8}{7}\cdot \dfrac{10}{24}= \dfrac{21}{\not10}\cdot \dfrac{8}{7}\cdot \dfrac{\not10}{24}= \dfrac{168}{168}=1\\ \\ \\ 1 \dfrac{5}{12} > 1 \Rightarrow a > b$