Question

ajutatima va rog frumos îmi trebuie pana la ora 15​

Answer 1

Răspuns:

B= 2/R2+3/R3+1/(R3+R2) (ADUNAM PRIMELE 2)

=(2R3+3R2)/R2R3 +1/(R3+R2)  (NUMITOR COMUN (R2+R3)R2R3

=[(2R3+3R2)(R2+R3) +1R2R3}/(R2+R3)R2R3

=(2R3R2+2*3+3*2+3R2R3+R2R3)/(R2+R3)R2R3

=(6R2R3+12)/[(R2+R3)R2R3]

6(R2R3+2)/[(R2+R3)R2R3]

6(R2R3+2)/ {2R3+3R2}  = A=3R2

6(R2R3+2) = 3R2 ({2R3+3R2}

6R2R3+12=6R2R3 +9*2

6R2R3+12=6R2R3+18 (??)

3R2 <R20; 3R2< 2R5 ; 3R2*R2/R2 <2R5*R5/R5 ; 6/R2 <10/R5 (NUMITOR COMUN R10)

6R5/R10 <10R2/R10

R180/R10 <R200/R10 (ADEVARAT)

INMULTIM CU 2R3+3R2/2R3+3R2

6(R2R3+2) *(2R3+3R2) /

Explicație pas cu pas: