Question

Ajutatima va rog la matematica dau coroana
Pentru functia f:R--R , f(x)=x^5-4x^3+2 , calculati $\lim_{x \to \ -1 } \frac{f(x)-f(-1)}{ x+1}$

Answer 1

din greseala am calculat f'(1) in loc de f'(-1)

f'(-1)=5×1-12×1= 5-12= -7

Answer 2

Răspuns:

f(-1)= (-1)⁵-4(-1)³+2=-1+4+2=5

f(x)-f(-1) = x⁵-4x³+2-5 = x⁵-4x³-3$\lim_{n \to \(-1)} \frac{x^{5} -4x^{3}-3}{x+1} = 0/0 =\lim_{n \to \(-1)} \frac{(x^{5} -4x^{3}-3)'}{(x+1)'} = \lim_{n \to \(-1)} \frac{5x^{4} -3*4x^{2}-0}{1+0} =$

= 5(-1)⁴-12(-1)² = 5-12 = -7