Question

Ajutatima va rog.Trebue sa efectuez inmultirea:a) - unu intreg si patru x la puterea a doua y·2XY; b) 0,6ab la puterea a doua·5a la puterea a doua b,c) 2x la puterea a doua y·(- unu supra √2y);d) -3√18ab·√2 supra lui trei a la puterea a treia b la puterea a doua. ex 7. Sa efectuez inpartirea: a) 12xy÷3x b)- doi supra lui dousapte x la puterea a treia y la puterea a patra ÷ unu supra lui noua x la puterea a doua y; c) 0,1a la puterea a patra b la puterea a doua ÷(-5ab la puterea a doua ); d)1,(5)a la puterea a sasea b la puterea a saptea÷0,(5)a la puterea a treia b la puterea a cincea.

Answer 1

b) 0,6ab²·5a²b=3a¹⁺²b²⁺1=3a³b³
c) 2x²y·(-1/√2y)=2x²y·(-y⁻¹/√2)=-2x²y¹⁻¹/√2=-2x²y°/√2=-2x²/√2=-2√2x²/2=-√2x²
d) -3√18ab·√2/3a³b²=-9√2ab·√2a⁻³b⁻²/3=(-9√2a¹⁻³b¹⁻²)/3=-3√2a⁻²b⁻¹=-3√/a²b 
ex 7. a) 12xy:3x =4x¹⁻¹y=4x°y=4y
b)-2/12x³y⁴:1/9x²y=-1/6x³y⁴·9x²y=-9/6·(x⁻³y⁻⁴)·x²y=-3/2·x⁻³⁺²y⁻⁴⁺¹=
-3/2x⁻¹y⁻³==-3/2xy³
c) 0,1a⁴b²:(-5ab²)=-0,02a⁴⁻¹b²⁻²=-0,02a³b°=-0,02a³ 
d)1,(5)=(15-1)/9=14/9
0,(5)=5/9
1,(5)a⁶b⁷:0,(5)a³b⁵=14a⁶b⁷/9:5a³b⁵/9=14/5·a⁶⁻³b⁷⁻⁵=14/5·a³b²=14a²b²/5=2,8a²b²