Question

Ajutatima va rogg...Simplificati fractia. 2+4+6+...4000 supra (nu am avut liniuta)3+6+9+...6000..Dau coroanaa

Answer 1

$\frac{2+4+6+8+....+4000}{3+6+9+....+6000}=\frac{2(1+2+3+....+2000)}{3(1+2+3+...+2000)}=\frac{2}{3}$

Answer 2

_2+ 4+ 6+ ... + 4 000_ =
 3+ 6+ 9+ ... + 6 000

_2( 1+ 2+ 3+ ... + 2 000)_ =
  3( 1+ 2+ 3+ ... + 2 000)

_2_
  3