Question

ajutatima va rogggggggg.ex 25.11 si 25.12

Answer 1

Cf= 70%

ms = 500g
C = 6%

C=md/ms*100 => md=C*ms/100 = 6*500/100 = 30g CH3-COOH

ms=md+mH2O => mH2O = ms-md = 500-30 = 470g

Cf = md/ms*100 <=> 70 = 30/30+mH2O*100 <=> 70(30+mH2O) = 30*100 <=> 2100+70mH2O = 3000 => 900 = 70mH2O => mH2O = 12,8571g

mH2O adaugata = 470-12,8571 = 457,142g

25.12

ms = 40g
C = 10% 

C=md/ms*100 => md= C*ms/100 = 10*40/100 = 4g H2SO4

n H2SO4 = 4/98 = 0,04 moli 

Zn + H2SO4 -> ZnSO4 + H2

n H2SO4 = n Zn = 0,04 moli

m Zn = 0,04*65 = 2,653g