Question

ajutatima varog mult si aratatimi si cum se rezolva
rezolva ecuatiile
a) radical din 3-2xla a doua =1
b)radical din 7x-2=-3
c)radical din 6x-4=0
d)radical din 15+3x=1-x
e)(x la a doua -4)*radical din x+1=o

Answer 1

a)√(3-2x²)=1
(√(3-2x²)²=1²
3-2x²=1
2x²=3-1
x²=2/2
x²=1
x1=1
x2=-1
S={-1,1}

b)√(7x-2)=-3
(√(7x-2)²=(-3)²
7x-2=9
7x=9+2
x=11/7

c)√(6x-4)=0
(√(6x-4))²=0
6x-4=0
6x=4
x=4/6
x=2/3

d) √(15+3x)=1-x
(√(15+3x))²=(1-x)²
15+3x=1-2x+x²
-x²+3x+2x+15-1=0
-x²+5x+14=0                inmultim -1
x²-5x-14=0
Δ=25+56=81
x1=(5-9)/2=-4/2=-2
x2=(5+9)/2=14/2=7
S={-2,7}