Question

AJUTAŢIMĂ VAROG URGENT DAU COROANA ŞI 100 PUNCTE!!!!​

Answer 1

a)

$\dfrac{1}{6} x < 3 \Leftrightarrow \dfrac{x}{6} < 3 \Leftrightarrow x < 6\cdot3 \implies x < 18$

b)

$-1\dfrac{1}{6} x > 42 \Leftrightarrow -\dfrac{7x}{6} > 42 \Big|\cdot(-1) \Leftrightarrow \dfrac{7x}{6} < -42 \Leftrightarrow x < -\dfrac{6 \cdot 42 }{7} \Leftrightarrow x < - 6 \cdot 6 \implies x < -36$

c)

$-\dfrac{3}{8} x < -12 \ \Big|\cdot(-1) \Leftrightarrow \dfrac{3}{8} x > 12 \Leftrightarrow x > \dfrac{8 \cdot 12 }{3} \Leftrightarrow x > 8 \cdot 4 \implies x > 32$

d)

$\dfrac{2}{3} x > 18 \Leftrightarrow x > \dfrac{3 \cdot 18 }{2} \Leftrightarrow x > 3 \cdot 9 \implies x > 27$

e)

$0,4 x > 2 \Leftrightarrow \dfrac{4x}{10} > 2 \Leftrightarrow x > \dfrac{2 \cdot 10 }{4} \Leftrightarrow x > \dfrac{20 }{4} \implies x > 5$

f)

$0,1 x < 10 \Leftrightarrow \dfrac{x}{10} < 10 \Leftrightarrow x < 10 \cdot 10 \implies x < 100$

g)

$-0,3 x < -9 \ \Big|\cdot(-1) \Leftrightarrow 0,3 x > 9 \Leftrightarrow \dfrac{3x}{10} > 9 \Leftrightarrow x > \dfrac{10 \cdot 9 }{3} \Leftrightarrow x > 10 \cdot 3 \implies x > 30$

h)

$-3 x > 1,1 \ \Big|\cdot(-1) \Leftrightarrow 3 x < -1,1 \Leftrightarrow 3x < -\dfrac{11}{10} \Leftrightarrow x < -\dfrac{11}{3 \cdot 10} \implies x < -\dfrac{11}{30}$

Answer 2

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