Question

Ajutatima vo rog din suflet!!!!!
si mai am unele
6x(5+4)-o+10=29-7:7
^
este o nu zero
si 33:(r+19)=80:2:5:4:2
trebuie. sa afli valoarea literei

Answer 1

6x(5+4)-o+10=29-7:7
6x9-o+10=29-1
54-o+10=28
64-o=28
o=64-28
o=36

33:(r+19)=80:2:5:4:2
33:(r+19)=40:5:4:2
33:(r+19)=8:4:2
33:(r+19)=2:2
33:(r+19)=1
r+19=1x33
r=33-19
r=14

32)
8+6x[4+27:(0+ux9)]=49+10:10
8+6x[4+27:(0+ux9)]=49+1
8+6x[4+27:(0+ux9)]=50
6x[4+27:(0+ux9)]=50-8
6x[4+27:(0+ux9)]=42
[4+27:(0+ux9)]=42:6
4+27:(0+ux9)=7
27:(0+ux9)=7-4
27:(0+ux9)=3
0+ux9=27:3
ux9=9
u=9:9
u=1

33)
[12-9:3+(12-9):3]xz+1=41
(12-3+3:3)xz=41-1
(9+1)xz=40
10z=40
z=40:10
z=4

Answer 2

6x9-o+10=29-1
54-o+10=28
54-o=28-10=18
54-o=18
o=54-18
o=36

33/(r+19)=80/2/5/4/2
33/(r+19)=40/5/4/2=8/4/2=2/2=1
33/(r+19)=1
r+19=33
r=33-19
r=14