Question

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Efecuati COMPLET!

122+12*{183:[( 2*3^2*5^3)^4 :( 2^4*3^7*5^12+ (2^8)^9 : 2^72 - 1^27*5^0]-9*(54-2^4*3)}

Answer 1

122+12×{183÷[(2×3 la puterea 2 ×5 la puterea3)totul la puterea 4 ÷(2 la puterea 4 ×3c la puterea 7 ×5 la puterea12 +(2 la puterea 8)la puterea9 ÷2 la puterea 72-1 la puterea27 ×5 la puterea 0]-9×(54-2 la puterea4 ×3)]}=

=122+12×{183÷(2la puterea 4 ×3 la puterea 8 ×5 la puterea 12)÷(2 la puterea4 ×3 la puterea 7×5 la puterea12+(2 la puterea72 ÷2 la puterea72=1×1]-9(54-16×3)]}=
=122+12×[183÷(2 la puterea 4-4 ×3 la puterea 8-7 ×5 la puterea12-12)-9(54-48)]=
=122+12×[183÷(2 la puterea0 -3 la puterea1 ×5 la puterea0)-9×6]=
=122+12 ×[183÷(1×3×1)-54]=
=122+12×(183÷3-54)=122+12×(61-54)=122+12×7=122+84=206