Question

Ajutoooor am nevoie de rezolvarea acestei probleme dau coroana

Answer 1

$m(\angle ABC)+m(\angle ACB)=180^{\circ}-45^{\circ}=135^{\circ}$
$m(\angle IBC)+m(\angle ICB)=\frac{m(\angle ABC)}{2}+\frac{m(\angle ACB)}{2}=\frac{135^{\circ}}{2}$
$m(\angle BIC)=180^{\circ}-\frac{135^{\circ}}{2}=\frac{360^{\circ}}{2}-\frac{135^{\circ}}{2}=\frac{225^{\circ}}{2}=112^{\circ}30'$