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Răspunsuri la întrebare
112g xg yg
FeCl2 +2 KOH= Fe( OH)2 +2 KCl
2.56 g 90g 2.74,5g
x=112.90 : 2 .56=90 g Fe(OH)2
Y=112.2.74,5 :2.56=149 g KCl
240g xg yg
CaCO3 =CaO + CO2
100g 56g 44g
se calculeaza puritatea CaCO3
p=mp.100 : mt
mp=80.300 : 100=240g CaCO3 pur
x=240.56 :100=
y=240.44 :100=105,6 g CO2
n=m:M n=nr.moli
n=105,6 g : 44g/moli=2,4 moli
VCO2=2,4moli .22,4litri/moli=
73g zg xg yg
2HCl +Mg =MgCl2 + H2
2.36,5g 24g 95g 2g
se afla md sol. de HCl
md=c.ms :100
md=36,5 .200:100=73g HCl
x=73.95 : 2,36,5=95g MgCl2
y=73.2:2.36,5=2g hidrogen
n=2g:2g/moli=1mol hidrogen
VH2=22,4 litri
z=73.24:2.26,5=24 g Mg
calculeaza singur masele moleculare
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