Question

AJUTOOOOR URGENT!!!
ABCD-patrat

AB = $6 \sqrt{5}$
M ∈ BC

BM = $2 \sqrt{5}$

d ( D, AM ) = ?

Answer 1

$A_{DAM}=\dfrac{DA\cdot d(M,DA)}{2}=\dfrac{6\sqrt5\cdot6\sqrt5}{2}=90\ cm^2$

AM se calculeaza cu T.P. din triunghiul ABM si se obtine AM=10√2 cm

Se scrie acum aria triunghiului
$A_{AND}=\dfrac{AM\cdot d(D,AM)}{2}\Rightarrow 90=5\sqrt2\cdot d(D,AM)\Rightarrow$

$\Rightarrow d(D,AM)=9\sqrt2\ cm$