Ajutoooorrr .... habar n.am cum sa incep
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㏒2(x²+mx+2m-1)
CE:x²+mx+2m-1<o
x²+mx+2m-1=2⇒
x²+mx+2m-1-2=0⇒
x²+mx+2m-3=0⇒
a=1
b=m
c=2m-3
Δ=b²-4ac⇒(m)²-4x1x2m-3⇒m²-8m+12=0
a=1
b=-8
c=12
Δ=b²-4ac⇒Δ=(-8)²-4x1x12⇒64-48⇒Δ=16⇒√Δ=√16⇒Δ=4
m1m2=-b+-√Δ|2a
m1=8+2|2⇒10|2⇒m1=5
m2=8-2|2⇒4|2⇒m2=2
m∈R
succes
CE:x²+mx+2m-1<o
x²+mx+2m-1=2⇒
x²+mx+2m-1-2=0⇒
x²+mx+2m-3=0⇒
a=1
b=m
c=2m-3
Δ=b²-4ac⇒(m)²-4x1x2m-3⇒m²-8m+12=0
a=1
b=-8
c=12
Δ=b²-4ac⇒Δ=(-8)²-4x1x12⇒64-48⇒Δ=16⇒√Δ=√16⇒Δ=4
m1m2=-b+-√Δ|2a
m1=8+2|2⇒10|2⇒m1=5
m2=8-2|2⇒4|2⇒m2=2
m∈R
succes
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