Question

Ajutooor....!!!!!!!!
Ex.15 (a)

Answer 1

$\frac{5 \frac{4}{9}: \frac{5}{36} *1 \frac{61}{64} }{6 \frac{1}{4}*1 \frac{3}{5}*5 \frac{3}{4} } : \frac{3 \frac{8}{9}: \frac{5}{13} }{7*5 \frac{4}{7} } * \frac{11 \frac{1}{3} * \frac{13}{2}:3 \frac{6}{7} }{3 \frac{1}{8}:6 \frac{2}{3} *1 \frac{8}{9} } =$

[tex] =\frac{ \frac{5*9+4}{9}* \frac{36}{5} * \frac{64+61}{64} }{ \frac{6*4+1}{4}*\frac{5+3}{5}* \frac{5*4+3}{4} } * \frac{7* \frac{5*7+4}{7}}{ \frac{3*9+8}{9}* \frac{13}{5} } * \frac{ \frac{11*3+1}{3} * \frac{13}{2}* \frac{7}{3*7+6} }{\frac{3*8+1}{8}* \frac{3}{6*3+2} *\frac{9+8}{9} } =[/tex]

[tex]=\frac{ \frac{49}{9}* \frac{36}{5} * \frac{125}{64} }{ \frac{25}{4}*\frac{8}{5}* \frac{23}{4} } * \frac{7* \frac{39}{7}}{ \frac{35}{9}* \frac{13}{5} } * \frac{ \frac{34}{3} * \frac{13}{2}* \frac{7}{27} }{\frac{25}{8}* \frac{3}{20} *\frac{17}{9} } = [/tex]

$=\frac{ \frac{49}{1}* \frac{1}{1} * \frac{25}{16} }{ \frac{5}{1}*\frac{1}{1}* \frac{23}{2} } * \frac{1* \frac{39}{1}}{ \frac{7}{9}* \frac{13}{1} } * \frac{ \frac{17}{3} * \frac{13}{1}* \frac{7}{27} }{\frac{5}{8}* \frac{1}{4} *\frac{17}{3} } =$

$= \frac{49*25}{16} *{ \frac{2}{23*5} * \frac{39}{1}* \frac{9}{13*7} } * \frac{17*13*7}{3*27} * \frac{8*4*3}{5*17} =$


$= \frac{7*1}{1} *{ \frac{2}{23*1} * \frac{1}{1}* \frac{1}{1*1} } * \frac{1*13*7}{1*1} * \frac{2*1*1}{1*1} =$

$= \frac{7*2*13*7*2}{23} = \frac{2548}{23}$