Question

AJUTOOOR. Ofer puncte
Radical din x^2-4x-1+x(nu aparține radicalului ultimul x) =7

Answer 1

$\sqrt{x^2-4x-1}= 7-x;x \leq 7\\ x^{2} -4x-1= 49-14x+ x^{2} \\ 10x=50 \\ x=5$
5∈DVA
S={5}

Answer 2

(√x²-4x-1)²=(7-x)²
x²-4x-1=49-14x+x²
x²-4x-1-49+14x-x²=0
10x-50=0
10x=50
x=5