Question

Ajutooor ...trebuie sa o rezolv pâna maine...cineva care ma poate ajuta?

Answer 1

1-PRODUS DE REACTIE,REPREZINTA O SUBSTANTA COMPUSA
2.SUBSTANTE SIMPLE SAU COMPUSE.

MFe3O4=232g/mol

232........................64gO2

100......................y

Y=6400/232

Y=27,58% O2

MFeO=56+16=72 g/mol

72.......................16

100.......................z

Z=1600/72=22,22

MFe2O3=160g/mol

160.....................48

100.......................t

T=30%

Raspuns :Fe2O3

4.S+O2→SO2

REACTANTI :SULF SI OXIGEN

SO2+ ½ O2→SO3

REACTANTI: DIOXID DE SULF SI OXIGEN

SO3+H2O→H2SO4

REACTANTI: TRIOXID DE SULF SI APA

5.Cl2+2Na→2NaCl

Cl2 +Mg→MgCl2

Cl2+Zn→ZnCl2

3Cl2+2Al→2AlCl3

6.9.4         Y             z

K2O+2H2O→ 2KOH

94         2X18   2x56

Y=9.4X2X18/94

Y=3,6 g apa consumata

Md=masa de hidroxid formata=z

Z=2x56x9,4/94

Z=11,2 g hidroxid de potasiu

ms=md+maparamasa

ms=11.2+43=54,2

mapa ramasa=46,6-3,6

mapa ramasa=43g

c=mdx100/ms

c=11,2x100/54,2

c=20%