Question

AJUTOOR!DOAR EX 3 PUNCTUL A)

Answer 1

$\displaystyle 3.~a)~~x=2\sqrt{5} +3\sqrt{7} ;~y=2\sqrt{5} -3\sqrt{7} \\\\ m_a=\frac{x+y}{2} =\frac{2\sqrt{5}+3\sqrt{7} +2\sqrt{5}-3\sqrt{7} }{2}=\frac{4\sqrt{5} }{2} =2\sqrt{5}$

Answer 2

$\it m_a=\dfrac{x+y}{2}=\dfrac{2\sqrt5+3\sqrt7+2\sqrt5-3\sqrt7}{2}=\dfrac{4\sqrt5}{2}=2\sqrt5$