Question

Ajutoor :( Se considera triunghiul ABC avand aria egala cu 15. Sa se calculeze sin A, stiind ca AB=6 si AC-10.

Answer 1

                 
$A_{\triangle ABC}= \frac{AB*AC*sinA}{2} \\ \\ 15= \frac{6*10*sinA}{2} \\ \\ sinA= \frac{2*15}{6*10}= \frac{30}{60} = \boxed{\frac{1}{2}}$