Question

AJUTOORR URGENT DAU COROANA ​

Answer 1

$x = \tfrac{ \sqrt{2} }{5} \times \big( \tfrac{1}{ \sqrt{2} } + \tfrac{2}{3 \sqrt{2} } \big) \\ x = \tfrac{ \sqrt{2} }{5} \times \tfrac{1}{ \sqrt{2} } + \tfrac{ \sqrt{2} }{5} \times \tfrac{2}{3 \sqrt{2} } \\ x = \tfrac{1}{5} + \tfrac{2}{15} \\ x = \tfrac{5}{15} \\ x = \tfrac{1}{3} \\ \\ \\ y = \big( \tfrac{1}{ \sqrt{2} } - \tfrac{2}{3 \sqrt{2} } \big) \times 5 \sqrt{2} \\ y = 5 - \tfrac{10}{3} \\ y = \tfrac{5}{3} \\ \\ \\\boxed{m _{a} = \frac{ \frac{1}{3} + \tfrac{5}{3} }{2} =\frac{\tfrac{6}{3}}{2}=\frac{2}{2}= \color{red}1}$

Answer 2

Răspuns:

Salut

Explicație pas cu pas:

x= $\frac{\sqrt{2} }{5}*(\frac{1}{\sqrt{2} } + \frac{2}{3\sqrt{2} }) = \frac{\sqrt{2} }{5}*(\frac{3}{3\sqrt{2} } + \frac{2}{3\sqrt{2} }) = \frac{\sqrt{2} }{5}* \frac{5}{3\sqrt{2} }= \frac{1}{3}$

y= $(\frac{1}{\sqrt{2} } - \frac{2}{3\sqrt{2} }) : \frac{1}{5\sqrt{2} }= (\frac{3}{3\sqrt{2} }- \frac{2}{3\sqrt{2} }) : \frac{1}{5\sqrt{2} }= \frac{1}{3\sqrt{2} }* \frac{5\sqrt{2} }{1}= \frac{5}{3}$

M a= $\frac{x+y}{2} = \frac{\frac{1}{3}+\frac{5}{3} }{2} = \frac{\frac{6}{3} }{2} = \frac{2}{2} =1$

PS: Am fost la masă de aceea am întârziat, scuze.

Sper că ți-am fost de folos!

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