Question

ajutoorva rog dau coroana, macar unul

Answer 1

1)
8^16:(2×2^4×2^10)^3-2^1-2^0=

=8^16: (2^(1+4+10))^3-2-1=

=8^16:(2^15)^3-1=

=8^16: 2^(15×3) -1=

=8^16: 2^45-1=

=(2^3)^16 :2^45 -1=

=2^(3×16) :2^45 -1=

=2^48: 2^45 -1 =

=2^(48-45) -1=

=2^3 -1 =

=8-1=

=7

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2)

[(3^3)^12 :3^2^5-56]:5=

=(3^(3×12) :3^32 -56):5=

= (3^36 :3^32-56):5=

=(3^(36-32)-56):5=

=(3^4 -56):5=

=(81-56):5=

=25:5=

=5



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3)

[(9^2- 2^4×5):1 +5^9:(5^2)^4]×2^2=

=[ (81-16×5):1 +5^9: 5^(2×4)]×4=

=[(81-80):1 +5^9 : 5^8]×4=

=(1:1 + 5^(9-8) )×4=

=(1+5)×4=

=6×4=

=24

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4)

[3^2×3^3+2^54:2^52+(3^5)^4:3^20]:31=

=[3^(2+3) + 2^(54-52)+3^ (5×4) :3^20]:31=

=(3^5+ 2^2+3^20:3^20):31=

=(3^5+ 4+1):31=

=(243+5):31=

=248:31=

=8
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5)

8^33:[4^32×2^34+(2^5×2^20)^5:(16×2^23)+(7^5:7^5-1)^32×4]=

=8^33:[(2^2)^32 ×2^34+(2^(5+20))^5:(2^4×2^23)+(1-1)^32×4]=

=8^33:[2^(2×32)×2^34+(2^25)^5: 2^27 +0^32 ×4]=

=8^33: (2^64×2^34+2^(25×5) :2^27+0×4)=

=8^33: (2^(64+34)+2^125 :2^27 +0)=

=8^33: (2^98 +2^(125-27) )=

=8^33: (2^98 +2^98)=

=(2^3)^33:(2^98+2^98)=

=2^99:(2^98+2^98)=

=2^99:(2 ×2^98)=

=2^99 : 2^(1+98)=

=2^99 : 2^99=

=1