Question

ajutor!
200:{[(7*d+144):25+132]×5-600}=2+0:10



altul
Impartiti nr 81 in 4 parti neegale incat daca inmultim prima parte cu doi , a doua parte o impartim la 2 ,la a treia parte adaugam 2,iar celei de a patra ,scadem 2,vom obtine rezultate egale



Multumesc!!!

Answer 1

200:{[(7*d+144):25+132]×5-600}=2+0:10
200:{[(7*d+144):25+132]×5-600}=2
[(7*d+144):25+132]×5-600=100
[(7*d+144):25+132]×5=700
(7*d+144):25+132=140
(7*d+144):25=140-132
(7*d+144):25=8
7*d+144=200
7*d=200-144
7*d=56
d=8

a+b+c+d=81
2a=b/2=c+2=d-2
b=4a
c=2a-2
d=2a+2
a+4a+2a-2+2a+2=81
9a=81
a=9
b=4*9=36
c=2*9-2=16
d=2*9+2=20