Question

Ajutor! (a-bi)/(b+ai) -i(b-ai)/(a+bi) Mersi in avans.

Answer 1

(a-bi)/(b+ai)-i(b-ai)/(a+bi)=(a-bi)/(b+ai)-(a+bi)/(a+bi)=(a-bi)(b-ai)/(b²-a²i²)-1=(ab-a²i-b²i+abi²)/(b²+a²)-1=(ab-a²i-b²i-ab)/(b²+a²)-1=-i(a²+b²)/(a²+b²)-1=-i-1