Question

ajutor aici va mulțumesc mult ​ arătați că e(x) = 0

Answer 1

Salut,

$E(x)=\dfrac{x}{x^2+x}-\left(\dfrac{x}{x-1}-\dfrac{x}{x+1}\right):\dfrac{2x}{x-1}=\\\\\\=\dfrac{x}{x(x+1)}-\dfrac{x(x+1)-x(x-1)}{(x-1)(x+1)}\cdot\dfrac{x-1}{2x}=\\\\\\=\dfrac{1}{x+1}-\dfrac{x^2+x-x^2+x}{x+1}\cdot\dfrac{1}{2x}=\\\\\\=\dfrac{1}{x+1}-\dfrac{2x}{x+1}\cdot\dfrac{1}{2x}=\dfrac{1}{x+1}-\dfrac{1}{x+1}=0.$

Ai înțeles rezolvarea ?

Green eyes.