Question

ajutor ajutor ajutor ajutor vă rog frumos urgent e foarte urgent.

$( \frac{4 \sqrt{5} }{3} \times - \frac{ \sqrt{7} }{2} a)( \frac{4 \sqrt{5} }{3} \times - \frac{ \sqrt{7} }{2} a) =$
$(a + 3)(a - 3) =$
$(2 \times + 1)(2 \times - 1) =$
$(5 \sqrt{2} \times - 3 \sqrt{3} {y})^{2}$
$( \frac{2}{7} \times - \frac{7}{3} {y})^{2} =$
​

Answer 1

(a+3)(a-3)= a²- 3²= a²- 9

(2x+1)(2x-1)= (2x)²-1²= 4x² - 1

sorry știu numai acestea

sper că te-am ajutat <3

Answer 2

Răspuns:

Sper ca te am ajutat

Explicație pas cu pas:

a. $(\frac{-4\sqrt{5} }{3} x \frac{\sqrt{7} }{2} a)x (\frac{-4\sqrt{5} }{3} x\frac{\sqrt{7} }{2} a)$

⇒$(\frac{-2\sqrt{5} }{3} x\sqrt{7a} ) x (\frac{-2\sqrt{5} }{3} x\sqrt{7a} )$⇒$(\frac{-2\sqrt{35a} }{3} )x(\frac{-2\sqrt{35a} }{3} )$⇒$\frac{2\sqrt{35a} }{3} x\frac{2\sqrt{35a} }{3} =\frac{140a^{2} }{9}$

b.$(a+3)(a-3)=a^{2} -3^{2} = a^{2} -9$

c.$(2x+1)(2x-1)=2x^{2} -1^{2} =4x^{2} -1$

d.⇒$(5\sqrt{2x} )^{2} -2x5\sqrt{2x} x3\sqrt{3y}+(3\sqrt{3y} )^{2}$⇒$25x 2x^{2} -30\sqrt{6xy} +9x3y^{2}$⇒$50x^{2} -30\sqrt{6xy} +27y^{2}$

e.$(\frac{-2}{7} x\frac{7}{3} y)^{2}$⇒$(\frac{-2}{3} y)^{2}$⇒$\frac{4}{9} y^{2}$