Question

Ajutor!!!
Am nevoie urgent de rezolvare​

Answer 1

T₁=2π√(l/g)

T₂=2π√(m/k)

T₂/T₁=n₁<=>2π√(m/k)/2π√(l/g)=n₁<=>n₁²=m/k/l/g<=>n₁²=mg/kl=>m/k=n₁²l/g

T₂'=2π√(m/k)

T₁'=2π√(l/(g+a))

T₂'/T₁'=n₂<=>2π√(m/k)/2π√(l/(g+a))=n₂<=>n₂²=m/k/l/(g+a)<=>n₂²=m(g+a)/kl<=>n₂²=n₁²l(g+a)/gl<=>n₂²=n₁²(g+a)/g<=>n₂²g=n₁²g+n₁²a<=>g(n₂²-n₁²)=n₁²a=>a=g(n₂²-n₁²)/n₁²

b)