Question

Ajutor!!!!!! Corana:/
Doar exercitiul 5

Answer 1

a·b=80/11
a·c=71/22
a·d·=145/33
a·(b-c+d)=a(80/11a-71/22a+145/33a)=a·1/a(80/11-71/22+145/33)=80/11-71/22+145/33
aduci la acelasi numitor si e simplu de terminat

Answer 2

$a*b=7 \frac{3}{11}= \frac{7*11+3}{11} = \frac{77+3}{11}= \frac{80}{11} \\ \\ a*c=3 \frac{5}{22}= \frac{3*22+5}{22} = \frac{66+5}{22}= \frac{71}{22} \\ \\ a*d=4 \frac{13}{33}= \frac{4*33+13}{33} = \frac{132+13}{33}= \frac{145}{33} \\ \\ a(b-c+d)=ab-ac+ad= \frac{80}{11}- \frac{71}{22}+ \frac{145}{33} = \\ \\ \frac{80*6-71*3+145*2}{66}= \frac{480-213+290}{66}= \frac{557}{66}$