Question

Ajutor cu problema!!Va rog.

Answer 1

Răspuns:

Explicație pas cu pas:

Answer 2

$\it m(\widehat{MON})=m(\stackrel\frown{MN})=144^o\\ \\ \mathcal{A}_{sector}=\dfrac{\pi R^2u}{360^o} \Rightarrow 36\pi=\dfrac{\pi\cdot R^2\cdot 144^o}{360^o} \Rightarrow R^2=\dfrac{360\cdot36\pi}{\pi\cdot144} =90\\ \\ R=\sqrt{90}=\sqrt{9\cdot10}=3\sqrt{10} cm$

$\it L_{cerc}=2\pi R=2\pi\cdot3\sqrt{10}=6\sqrt{10}\ \pi\\ \\ \mathcal{A}_{disc}=\pi R^2=\pi\cdot90=90\pi\ cm^2$

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