Question

Ajutor! Cum se face rezolvarea corectă a următoarelor puteri:a) (5/2-2/3+1/6)^5; c) (3 + 1/4-5/2)^3; d) (3/2-1/5-7/10)^3

Answer 1

a) $( \frac{5}{2}- \frac{2}{3}+ \frac{1}{6})^{5} =\frac{5*3}{2*3} - \frac{2*2}{3*2}+ \frac{1}{6}= \frac{15}{6}- \frac{4}{6}+ \frac{1}{6}=(\frac{15-4+1}{6})^{5}= (\frac{12}{5})^{5}= 2^{5}$

b) $(3+ \frac{1}{4}- \frac{5}{2})^{3}= \frac{12+1-10}{4}= (\frac{3}{4})^{3}= \frac{27}{64}$

c) $( \frac{3}{2}- \frac{1}{5}- \frac{7}{10})^{3}= \frac{15-2-7}{10}= \frac{6}{10} = (\frac{3}{5} ) ^{3} = \frac{27}{125}$