Question

Ajutor!!!Dau 15 puncte si coroniţa!!!Am nevoie URGENT!a)Aflati elementele multimii A={x€Z|8/2x-1€Z}
b)Aflati c.m.m.m.c al numerelor naturale a si b,date de relatiile:a=[(4*5*25^200)*(2^100*8*5^3)]:(4^50*625^4*5^2*10),b=2*3+2[(3*5^2-2^3*3^2:3^2+3*11):4^0]

Answer 1

a) pentru ca 8/2x -1 sa apartina lui z , cu x apartine lui z , 2x-1 trb sa fie divizori ai lui 8

D8={+-1, +-2,+-4,+-8}

si calculezi toate ecuatiile reiesite

2x-1=1

x=1

2x-1=-1

x=0

2x-1=2

2x=3/2

2x-1=-2

x=1/2

2x-1=4

x=5/2

2x-1=-4

x=-3/2

2x-1=8

x=4.5

2x-1=-8

x=3.5

A={0,1}

b) a=(2^2*5^401)(2^103*5^13)/(2^100*5^41282)

a= 2^4*5^2=16*25=400

b=6+2(3*25-8*9+33)=6+2(75+72+33)=6+2(75+105)=6+2*108=6+360=366

400=2*5*2*5*2*2=2^4*5^2

366=2*3*61

c.m.m.m.c=2*2*2*2*5*5*3*61=73200