Question

Ajutor. Dau coroana!

Answer 1

$log_{a}12 = log_{a}3*4 = log_{a}3+ log_{a}4= log_{a}3+2 log_{a}2=n+2m \\ log_{a} \sqrt[3]{18}= log_{a} 18^{ \frac{1}{3} }= \frac{1}{3}( log_{a}9+ log_{a}2)= \frac{1}{3}(2n+m)$